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The sum of three integers is 66. The second is 2 more than the first, the third is 4 more than twice the first. What are the integers?

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Let the integers be x, y and z.

Given that the sum of the three integers is 66.

==> x + y + z = 66..............(1)

Also, given that the second integer (y) is 2 more than the first (x).

==> y = x + 2...

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