The sum of three integers is 66. The second is 2 more than the first, the third is 4 more than twice the first. What are the integers?
Let the integers be x, y and z.
Given that the sum of the three integers is 66.
==> x + y + z = 66..............(1)
Also, given that the second integer (y) is 2 more than the first (x).
==> y = x + 2...
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