Okay, so the first thing you need to do is set up your equations.
First, if the sum of the two is 240 then x+y=240.
Second, if x divided by 9 is y, then x/9=y. Another way to put that is 9x=y because if x divided by 9 is y, then 9 of x makes one of y.
To solve for x, you want to first get rid of y in the first equation. Since you know that 9x=y, you just plug that in.
So you know that 10x=240. To find x you divide both sides by 10.
So that leaves you x = 24
To check this, multiply 24 by 9. That gets you 216. 216+24 is 240.
So we got the right answer...
The sum of integers x & y is 240. if x was divided by 9, the result would be y. what is the value of x?
The first statement gives us: x + y = 240
The second statement gives us: x/9 = y
Now that you have two equations, you can solve for x and y.
As per the data given in the question:
x + y = 240 ... ... (1)
and y = x/9 ... ... (2)
Substituting value of y from equation (2) in equation ( we get:
x + x/9 = 240
Or: (9x + x)/9 = 240
Or: 10x/9 = 240
Or: 10x = 240*9 = 2160
Or: x = 2160/10 = 216
Substituting this value of x in equation (1) we get:
216 + y = 240
Therefore: y = 240 - 216 = 24
x = 216 and y = 24
From the sentence given, x divided by 9 equals y , we understand that we can have the one unknown y, and 9y eqivalent to x but instead of x. So now sum of x +y is as good as sum of 9y and y which is algebraically 10y, but is equal to 240 as per the condition given.So now, 10y equals 240, and that means y has has to be one 10th of 240 and that is 24. Therefore, the value of the other unknown, that is 9y, is 24 nines are the 216.