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Consecutive even integers are even integers that follow one another, such as 2, 4, 6, 8, and so on. Each consecutive even integer is 2 more than the previous one.
So if the first integer is n, then the next even integer is n + 2, the next one (third) is (n+2) + 2 = n+ 4, and the fourth one is (n+4) + 2 = n+6.
According to the problem, the sum of these four integers is 62, so
n + (n+2) + (n+4) + (n+6) = 62
SImplifying the left side, get
4n + 12 = 62
4n = 50
n = 12.5 which is not an integer. This means there is no 4 consecutive even integers such that their sum is 62.
Let cosecutive integers are 2x,2x+2,2x+4,2x+6.
(Since differnce between two consecutive integers is `+-2` )
Thus by given condition
These are not integer.
So there is some problem in question.
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