# the sum of four consecutive even integers is 62 what are the four integers?

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**Consecutive even integers** are even integers that follow one another, such as 2, 4, 6, 8, and so on. Each consecutive even integer is 2 more than the previous one.

So if the first integer is n, then the next even integer is n + 2, the next one (third) is (n+2) + 2 = n+ 4, and the fourth one is (n+4) + 2 = n+6.

According to the problem, the sum of these four integers is 62, so

n + (n+2) + (n+4) + (n+6) = 62

SImplifying the left side, get

4n + 12 = 62

4n = 50

n = 12.5 which is not an integer. This means **there is no 4 consecutive even integers such that their sum is 62.**

Let cosecutive integers are 2x,2x+2,2x+4,2x+6.

(Since differnce between two consecutive integers is `+-2` )

Thus by given condition

`2x+(2x+2)+(2x+4)+(2x+6)=62`

`8x+12=62`

`8x=50`

`x=25/4=6.25`

Thus

2x=2x6.25=12.50

2x+2=14.50

2x+4=16.50

2x+6=18.50

These are not integer.

So there is some problem in question.