the sum of four consecutive even integers is 62 what are the four integers?
Consecutive even integers are even integers that follow one another, such as 2, 4, 6, 8, and so on. Each consecutive even integer is 2 more than the previous one.
So if the first integer is n, then the next even integer is n + 2, the next one (third) is (n+2) + 2 = n+ 4, and the fourth one is (n+4) + 2 = n+6.
According to the problem, the sum of these four integers is 62, so
n + (n+2) + (n+4) + (n+6) = 62
SImplifying the left side, get
4n + 12 = 62
4n = 50
n = 12.5 which is not an integer. This means there is no 4 consecutive even integers such that their sum is 62.
Let cosecutive integers are 2x,2x+2,2x+4,2x+6.
(Since differnce between two consecutive integers is `+-2` )
Thus by given condition
These are not integer.
So there is some problem in question.