We have xn = 1 / (n-1) and we have to study the monotony for n>=2.

To find the monotony of xn for n>=2, we find the derivative of xn with respect to n

(xn)' = -1/ (n-1)^2

for n>=2, xn' = -1 / (2 - 1)^2 < 0.

**Therefore xn is decreasing for all value of n >=2.**

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