What is the sampling distribution of the proportion of adults who smoke out of a random sample of 300? In a study where 300 randomly selected adults were asked whether they smoked, 22.4% were found...

What is the sampling distribution of the proportion of adults who smoke out of a random sample of 300?

In a study where 300 randomly selected adults were asked whether they smoked, 22.4% were found to be smokers. Using this information, give an estimate for the probability that in another random sample of 300, 50 will be found to smoke.

 

1 Answer | Add Yours

mathsworkmusic's profile pic

mathsworkmusic | (Level 2) Educator

Posted on

The sampling distribution of the number out of a random sample of 300 adults who smoke, `x`, can be assumed to be Binomial(300,` ``p`) where `p` is the true proportion who smoke in the (adult) population as a whole. The sampling distribution of the proportion in the sample who smoke `hat(p) = x/300` can be assumed to be Binomial(300,`p`)/300

With an estimate for `p` of `hat(p)=0.224` we can estimate the distribution of the sample count (over repeated samples) to be Binomial(300,`hat(p)=0.224`).

Using this estimated distribution, we can estimate the probability that 50 adults out of a random sample of 300 will smoke. This is

`(300!)/(50!250!)hat(p)^50(1-hat(p))^250 = 0.0087`

The sampling distribution of `hat(p)` can be assumed to be Binomial(300,p)/300.

The probability that 50 adults will be found to be smokers in a random sample of 300 is estimated as 0.0087.

 

 

 

We’ve answered 318,984 questions. We can answer yours, too.

Ask a question