What was the mistake committed by the student in the following case: A student was trying to make copper(II)sulphate crystals from copper(II)oxide and dilute sulphuric acid, instead of blue crystals, his final product was a white compound. What mistake did the student make? a. adding excess copper (II) oxide b. heating the filtrate to dryness c. using concentrated sulphuric acid instead of dilute sulphuric acid d. using excess dilute sulphuric acid

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Copper oxide reacts with sulfuric acid to form copper sulfate. The color of copper sulfate is dependent on the degree of hydration. The blue crystals of copper sulfate that are usually seen are crystals of the pentahydrate form CuSO4.5H20

If the hydrated copper sulfate is heated further and the water...

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Copper oxide reacts with sulfuric acid to form copper sulfate. The color of copper sulfate is dependent on the degree of hydration. The blue crystals of copper sulfate that are usually seen are crystals of the pentahydrate form CuSO4.5H20

If the hydrated copper sulfate is heated further and the water is evaporated gradually, the resulting form of copper sulfate turns a pale green and finally turns white in color.

In the procedure followed by the student that you have described, the white compound that was formed is due to the student's mistake of heating the filtrate to dryness. This converted the pentahydrate form to anhydrous copper sulfate which is a white colored compound.

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