Strontium 90 is an element with a half life cycle of 28 days. How long would it take a sample of 448 g to decay to 7 g?

Expert Answers
lemjay eNotes educator| Certified Educator

To solve, let's apply the formula of half-life which is:

`A = A_o 0.5^(t/t_(1/2))`

where `A` - amount of substance left , `A_o` - original amount of substance, 

          `t_(1/2) ` - half-life of the substance and `t` - elapsed time

Substitute the given values `A=7g` , `A_o = 448g` , and `t_(1/2)=28 days` to the formula.


Then, isolate t.

To do so, divide both sides by 448.



Then, take the natural logarithm of both sides of the equation.


As per property of logarithm, `ln 0.5^(t/28)` becomes `t/28 ln 0.5` .

`ln(7/448)= t/28*ln0.5`

Then, multiply both sides by 28.

`28*ln(7/448)= (t/28*ln0.5)*28`

`28ln(7/448) = t*ln0.5`

Then, divide both sides by ln 0.5.

`(28ln(7/448))/ln0.5= (t*ln0.5)/(ln0.5)`



Hence, it takes 168 days for the 448g Strontium-90 to decay to 7g.