# A string is divided into three segments, so that thesegments possess fundamental frequencies in the ratio1 : 2 : 3. Then the lengths of the segments are in theratio

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Student Comments

pramodpandey | Student

We know

`nu=(1/(2pi))sqrt(g/l)`

`` Let `k=(1/2pi)sqrt(g)`

`nu=k/sqrt(l)`

`nu sqrt(l)=k`

`nu_1:nu_2:nu_3=1:2:3`

`nu_1 sqrt(l_1)=nu_2sqrt( l_2)=nu_3sqrt( l_3)=k`

`sqrt(l_1)=sqrt(l_2).2`

`l_1/l_2=4/1`

`2sqrt(l_2)=3sqrt(l_3)`

`l_2/l_3=9/4`

`l_1:l_2:l_3=36:9:4`

`` where l_1,l_2 and l_3 are lengths of string.

pramodpandey | Student

you are right but actually you work out problem then see what is answer.May possible printing error or else ?