A stone is thrown straight up from the edge of a roof, 1000 feet above the ground, at a speed of 14 feet per second. What is the velocity of the stone when it hits the ground?
The equation for displacement is `s(t)=-16t^2+v_0t+s_0` where `v_0` isthe initial velocity and `s_0` is the initial displacement. We adopt the convention that velocity towards the earth is negative:
So we have...
(The entire section contains 107 words.)
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