The equation for a free falling body (no acceleration except gravity -- thus ignoring air resistance, etc...) is
`h(t)=-16t^2+v_0t+h_0` where
h -- the height in feet at time t
t -- the time in seconds
`v_0` -- the initial velocity in feet per second.. (Positive if away from the Earth, and negative if towards the Earth.)
`h_0` -- the initial height in feet.
The velocity function is the derivative of the displacement function so with v as the velocity in feet per second at time t we get:
`v(t)=-32t+v_0`
To find the initial height, we use the given information that at time t=10 the height is 0 and the initial velocity is 10fps (again positive since it is directed away from the ground):
`0=-16(10)^2+10(10)+h_0`
`=>h_0=1500"ft"`
To find the final velocity we substitute t=10 into the velocity formula:
`v_(10)=-32(10)+10` or v=-310fps.
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The initial height was 1500 ft and the final velocity was -310 fps.
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