A stock solution of 10M NaOH is prepared. From this solution, you need to make 250mL of 0.375M solution. How many mL will be required? The answer if 9.4mL but I don't know how to get that.

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suppose, V ml is the volume required from the stock solution,

and then the number of moles in that V will be, n1

n1 = 10 mol/dm3 x (v/1000)

n1 = v/100

This amount of moles are in 250mL of 0.375M solution,

therefore,

0.375 = (v/100)/250 x 1000

0.375...

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suppose, V ml is the volume required from the stock solution,

and then the number of moles in that V will be, n1

n1 = 10 mol/dm3 x (v/1000)

n1 = v/100

 

This amount of moles are in 250mL of 0.375M solution,

therefore,

0.375 = (v/100)/250 x 1000

0.375 = v/25

v = 9.375 mL

 

But the amount you can measure by a measuring cylinder (10 mL) is 9.4 mL. (0.1 mL accuracy)

Therefore the answer is 9.4 mL

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