The car's acceleration can be calculated as `a = (Delta V)/t` , where `Delta V` is the change in its velocity during the interval of time t. Since the car is originally stationary, the initial velocity is zero, and the change of velocity is equal to the final velocity:

`Delta...

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The car's acceleration can be calculated as `a = (Delta V)/t` , where `Delta V` is the change in its velocity during the interval of time t. Since the car is originally stationary, the initial velocity is zero, and the change of velocity is equal to the final velocity:

`Delta V = 15 m/s`

and the time interval is t = 5 s.

So `a = (15 m/s)/( 5s) = 3 m/s^2`

**The acceleration equals 3 m/s^2.**

The force required to reach this acceleration can be found by the second Newton's Law:

`F = ma` , where m is the mass of the car.

`F = (1500 kg)(3 m/s^2) = 4500 N`

**The force required is 4500 N.**