you need to know the following equations inorder to do this calculation.

`omega = omega_0+alpha*t`

`tau= I*alpha`

For our question;

omega_0 = 0 because it starts from rest.

omega = 2000/60*2*pi/3 = 69.813rad/s

t = 3s

Then `alpha = (omega-omega_0)/t`

`= 69.813/3`...

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you need to know the following equations inorder to do this calculation.

`omega = omega_0+alpha*t`

`tau= I*alpha`

For our question;

omega_0 = 0 because it starts from rest.

omega = 2000/60*2*pi/3 = 69.813rad/s

t = 3s

Then `alpha = (omega-omega_0)/t`

`= 69.813/3` `rad(s^-2)`

torque applied ;

tau= I*alpha

= `2.5 x 10^-5xx69.813/3`

= `5.818xx10^-4 `

The angular velocity of the disk = 2000rpm = 2000/60 rps

when achieving full velocity the time taken to that is 3s.

So at 3s the number of revolutions= 2000/60*3 = 100

**So it take 100 revolutions to achieve max angular velocity.**