# A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows down and comes to a stop in 10 s. What was the girl’s...

A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows down and comes to a stop in 10 s. What was the girl’s acceleration during each of the three time periods? What was her acceleration for the entire trip?

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### 3 Answers

We have three time intervals to consider here. In the first, the girl starts at 0 m/s and reaches 1.4 m/s in 3 seconds. The acceleration is given by (v - u)/t, where v is the final velocity, u is the initial velocity and t is the time taken.

a = (1.4 - 0)/3 = 7/15 m/s^2.

In the second interval of time, the girl travels at a constant speed of 1.4 m/s for 6 seconds. The acceleration during this interval is 0.

In the third interval, the girl slows down from 1.4 m/s and comes to a halt in 10 seconds. The acceleration here is -0.14 m/s^2.

Over the entire trip the acceleration is 0 as the initial velocity and the final velocity are equal.

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Okay, sorry.. I had to edit my question so it would fit! the real quesiton is:

A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows down and comes to a stop during a 10.0-s period. What was the girl’s acceleration during each of the three time periods? What was her acceleration for the entire trip?