# a standard deck of cards contain 52 cards. one cards is selected from the deck A) compute the probobility of randomly selecting a nine or ten B) compute the probobility of randomly selecting a nine...

a standard deck of cards contain 52 cards. one cards is selected from the deck

A) compute the probobility of randomly selecting a nine or ten

B) compute the probobility of randomly selecting a nine or ten or ace

C) compute the probobility of randomly selecting a four or spade

p (nine or ten )= type a interger or a siplified fraction

*print*Print*list*Cite

### 1 Answer

There are four 9 cards out of 52 cards, so the probability of getting 9 in a deck of 52 cards is P(9) = 4/52. The same goes with the probability of getting 10 in a deck of 52 cards, P(10) = 4/52. So, solving for

A) P (9 or 10) = P(9) + P(10) = 4/52 + 4/52 = 8/52 = 2/13

For B), you just have to get the probability of getting an ace. There are four aces in a standard deck of cards, so P(ace) = 4/52. Do the same formula as the first.

B) P(9 or 10 or ace) = P(9) + P(10) + P(ace) = 4/52 + 4/52 + 4/52

= 12/52 = 3/13

For C), there are four 4 cards in a deck, so the probability is P(4) = 4/52. Likewise, there are 13 spades in a deck of 52, so P(spade) = 13/52. There is a card that is 4 and spade, so P(4 and spade) = 1/52.

C) P(4 or spade) = P(4) + P(spade) - P(4 and spade)

= 4/52 + 13/52 - 1/52 = 16/52 = 4/13