A square has a side 5 centimeters shorter than the side of a second square.  The area of the larger square is four times the area of the smaller square. Find the side of each square.

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Let the side of the first square be x.

The side of the second square is y.

Given that the side of square 1 is 5 cm shorter than square 2.

==> x = y-5 ...........(1)

Also, the area of the larger square ( square 2) is 4 times the area of square 1.

==> y^2 = 4*x^2 .........(2)

We will solve by substitution.

We will substitue (1) into (2).

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