A spring-loaded gun, fired vertically, shoots a marble 9.0 m straight up in the air. What is the marble's range if it is fired horizontally from 1.8 m above the ground?

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Borys Shumyatskiy eNotes educator | Certified Educator

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Because nothing is specified, I suppose that the vertical shot is made (formally) from the height 0. Also we'll ignore air resistance.

Then the height of the marble during the first shot is

`H_1(t) = V_0*t-(g*t^2)/2,`

where `V_0` is the initial velocity of a marble.

This height...

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