A sports car go from rest to 32 m/s in 3.88s. The same car can come to a full stop from that speed in 3.96 s. What is the ratio of starting to stopping accelerations? Show your work please.
Acceleration is the rate of change of velocity.
For the starting phase:
`a=(32-0)/3.88=32/3.88 =8.247 m/s^2`
For the stopping phase,
`a=(0-32)/3.96=-32/3.96 =-8.0808 m/s^2`
The negative sign indicates that here retardation operates actually.
So, the ratio of starting to stopping acceleration of the sports car is `8.247/-8.0808=-1.02`