# A spherical snowball is melting in such a way that its diameter is decreasing at rate of 0.1 cm/min. At what rate is the volume of the snowball decreasing when the diameter is 10 cm. (Note the answer is a positive number).

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We are given the rate of decrease of the diameter `(dd)/(dt)=.1"cm"/"min" ` . We are asked to find the rate of the decrease of the volume when the diameter is 10cm:

The formula for the volume of a sphere is `V=4/3pir^3 ` .

The derivative is ` (dV)/(dt)=4pir^2(dr)/(dt) `

If the diameter is 10cm, the radius is 5cm. Also, if `(dd)/(dt)=.1 ` then `(dr)/(dt)=.05 `

Then substituting the given values:

`(dV)/(dt)=4pi(5)^2(.05)~~15.71 `

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