The speed of an ultrasonic sound frequency 45 kHz in air is 342 m/s. What is the air temperture?

1 Answer | Add Yours

sciencesolve's profile pic

sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted on

You should use the equation that relates the speed of sound and temepratures such that:

`v_(sound) = 331m/s + 0.6T` .

The problem provides the value of speed of sound, hence, substituting 342 m/s for `v_(sound)`  yields:

`342 m/s = 331 m/s + 0.6T =gt 0.6T = 342 m/s- 331 m/s`

`0.6T = 11 m/s =gt T = 11/0.6 =gt T = 11/(6/10) `

`T = 11*10/6 =gt T = 11*5/3 = 18.3^oC`

Hence, evaluating the temperature under the given conditions yields `T = 18.3^oC.` 

Sources:

We’ve answered 318,919 questions. We can answer yours, too.

Ask a question