# Solving a quadratic equation gives roots that add up to 125 and the product is 98. What is the equation.

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### 2 Answers

A quadratic equation has two roots. Let the roots be a and b. The equation can be written as:

(x - a)(x - b) = 0

=> x^2 - ax - bx + ab = 0

=> x^2 - x(a + b) + ab = 0

It is given that the sum of the roots is 125 and the product is 98. Substituting these values gives x^2 - 125x + 98 = 0

**The quadratic equation with sum of roots 125 and product of roots 98 is x^2 - 125x + 98 = 0.**

Quadratic equations should contain at least two numbers which can de subduded in the equation.

In this case there are 125 and 98

x+y=125

xy=98

Form a equation in terms of y

x=125-y

Subtitue it in the product equation

(125-y)y=98

y^2-125y=98

y^2-125y-98=0

The equation is y^2-125y-98=0