# Solve the quadratic equation by factoring: 2x^2+14=0

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### 2 Answers

The quadratic equation 2x^2+14=0 has to be solved.

2x^2+14=0

=> 2(x^2 + 7 ) = 0

x^2 + 7 = 0

=> x^2 = -7

=> x = `sqrt(-7)` and x = `-sqrt(-7)`

=> x = `sqrt7*i` and x = `-sqrt7*i`

**The solution of the equation 2x^2+14=0 is x = `sqrt7*i ` and **`x = -sqrt 7*i`

`2x^2 + 14 =0`

`2(x^2 +7)= 0`

As the equation is equal to zero, each factor equals zero. Thus:

`2!=0`

`x^2+7=0`

`therefore x^2=-7`

`therefore x= +- sqrt (-7)`

`therefore` thre is no normal solution for this equation due to the negative symbol inside the square root.

`therefore` **no solution **or if you use complex numbers** = `isqrt7` **