You need to separate the variables such that:

`dy = (2log x dx)/(x log x)`

You need to divide by log x to the right side such that:

`dy = (2/x) dx`

You need to integrate both sides such that:

`int dy = int (2/x) dx`

`y = 2ln|x| + c`

`y = ln (x^2) + c`

**Hence, evaluating the general solution to equation yields `y = ln (x^2) + c.` **

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