Solve for x and y 3x+y = 5 x-2y=4Solve for x and y 3x+y = 5 x-2y=4
4 Answers
hala718 | High School Teacher | (Level 1) Educator Emeritus
3x + y = 5..........(1)
x - 2y = 4 ..........(2)
First let us use the elimination method.
Let us multiply (1) by 2 and add to (2):
==> 7x = 14
==> x = 2
Now using the substitution method substitute x velue in (2)
x-2y = 4
2 - 2y = 4
2-4 = 2y
-2 = 2y
==> y= -1
The solution is:
x= 2 and y= -1
thewriter | College Teacher | (Level 1) Valedictorian
The given equations are:
3x+y=5.................(1) and
x-2y=4..................(2)
Multiplying (1) by 2 we get 6x+2y=10;
now adding (2) to this we get 6x+x+2y-2y=10+4, or 7x=14, x=14/7=2.
Substitute x=2 in (2). This gives 2-2y=4 or -2y=2 or y=2/(-2)= -1.
Therefore from the given equations we get x=2 and y=-1.
neela | High School Teacher | (Level 3) Valedictorian
3x+y =5 .......(1)
x-2y = 4...........(2)
From the second equation x= 2y+4. Putting this in in (1)
3(2y+4)+y =5
6y+12+y =5
7y = 5-12 =-7,
y = -7/7 = -1.
From (1) : 3x+y =5,
3x+(-1) = 5
3x= 5+1= 6
3x= 6
x = 6/2=3.
So x = 3 and y = -1
giorgiana1976 | College Teacher | (Level 3) Valedictorian
We'll solve the system using the elimination method.
We'll note the equations of the system as:
3x+y = 5 (1)
x-2y = 4 (2)
We'll multiply the first equation by 2:
2*(3x+y) = 2*5
We'll remive the brackets:
6x + 2y = 10 (3)
We'll add (3) to (2):
6x + 2y+x-2y = 4+10
We'll eliminate like terms:
7x = 14
We'll divide by 7:
x = 2
We'll go into the second equation:
2-2y = 4
We'll subtract 2 both sides:
-2y = 2
We'll divide by -2:
y = -1
The solution of the system is: {(2 , -1)}.