solve for x if x^3 +x^2 +x +1 = 0
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Tushar Chandra
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We have to solve for x: x^3 +x^2 +x +1 = 0
x^3 +x^2 +x +1 = 0
=> x^2( x + 1) + 1(x + 1) = 0
=> (x^2 + 1)(x + 1) = 0
x + 1 = 0
=> x = -1
x^2 + 1 = 0
=> x^2 = -1
=> x = i , -i
The values of x are -1 , i , -i
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hala718
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Given the equation:
x^3+ x^2 + x +1 = 0
We need to find x values that satisfies the equation.
First we will simplify by factoring.
We will factor x^2 from the first two terms.
==> x^2 ( x+1) + x+1 = 0
Now we will factor x+1
==> (x+1)*(x^2+1) = 0
==> x+1 = 0 ==> x1= -1
==> x^2 + 1 = 0 ==> x= +-i
Then, there are 3 roots for the equation.
==> x= { -1, i, -i}