# Solve for x: log3 x=5the 3 is a base

*print*Print*list*Cite

### 2 Answers

The logarithm function is defined such that log(a) b = c

=> b = a^c

Here it is given that log3 x = 5

=> x = 3^5

=> x = 243

**The required value of x = 243.**

First, we'll impose that the root of the equation must respect the constraint of existence of logarithm.

x>0

We'll solve the equation taking antilogarithm:

log3 x=5

x = 3^5

x = 243

**Since the value of x is positive, then the root of the equation is x = 243.**