Solve for x: (hint: factor) x2-8x+12=0
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You also may substitute `16-4` for `12` such that:
`x^2 - 8x + 16 - 4 = 0`
You need to group the terms such that:
`(x^2 - 4) + (-8x + 16) = 0`
You should convert the difference of squares `x^2 - 4` into a product using the...
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