Solve for x: (hint: factor) x2-8x+12=0

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You also may substitute `16-4`  for `12`  such that:

`x^2 - 8x + 16 - 4 = 0`

You need to group the terms such that:

`(x^2 - 4) + (-8x + 16) = 0`

You should convert the difference of squares `x^2 - 4`  into a product using the...

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