# Solve for x given that log(2)x + log (4)x +log(8)x = 11 ( the number in brackets is the base.

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### 1 Answer

We have to solve log(2)x + log (4)x +log(8)x = 11.

Use the relation log(a) b = log b/ log a, for any common base.

log(2)x + log (4)x +log(8)x = 11

can be written as log to the base 2

=> log(2)x + log(2)x/log(2)4 + log(2)x/log(2)8 = 11

=> log(2)x + log(2)x/2 + log(2)x/3 = 11

=> log(2)x [ 1 + 1/2 + 1/3] = 11

=> log(2)x [ 11/6] = 11

=> log(2) x = 6

=> x = 2^6

=> x = 64

**The required value is x = 64**