Solve for x. f(g(x))=0 f(x)=x^2-4 and g(x)=(x+3)

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We are given that f(x) = x^2 - 4 and g(x) = x + 3. We have to solve for x given that  f(g(x)) = 0.

f(g(x)) = 0

=> f( x +3) = 0

=> (x +3)^2 - 4 = 0

=> (x + 3 - 2)(x + 3 + 2) = 0

(x + 3 - 2) = 0

=> x = -1

(x + 3 + 2) = 0

=> x = -5

The solutions for x are x = -1 and x = -5

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