Solve for x. 3x^3+x^2-48x=16

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The equation 3x^3+x^2-48x=16 has to be solved for x.

3x^3+x^2-48x=16

=> 3x^3+x^2-48x - 16 = 0

=> x^2(3x + 1) - 16(3x + 1) = 0

=> (x^2 - 16)(3x + 1) = 0

=> (x - 4)(x + 4)(3x + 1) = 0

x = 4, x = -4 and x = -1/3

The solution of the equationĀ 3x^3+x^2-48x=16 is {-4, -1/3, 4}

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