Solve for x to 3 decimal places: 3^2x= 4^(1-3x)

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embizze eNotes educator| Certified Educator

Solve for x to three decimal places: `3^(2x)=4^(1-3x)` :

Take the logarithm of both sides:

`ln(3^(2x))=ln(4^(1-3x))`   Now use `lna^x=xlna` :

`=> 2xln3=(1-3x)ln4`



`=> x=(ln4)/(2ln3+3ln4)`



The solution is `x~~0.218`




lilian-0716 | Student

Hi, should x be to the power of?can you explain it in a simpler form