# Solve x^3+3*x^2+2*x = 0

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

The equation x^3+3*x^2+2*x = 0 has to be solved.

x^3+3*x^2+2*x = 0

=> x*(x^2+3*x+2) = 0

=> x*(x^2 + 2x + x + 2) = 0

=> x*(x(x + 2) + 1(x + 2)) = 0

=> x*(x + 1)(x + 2) = 0

=> x = 0, x = -1 and x = -2

The solution of the equation x^3+3*x^2+2*x = 0 is {-2, -1, 0}

lochana2500 | Student, Undergraduate | (Level 1) Valedictorian

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`x^(3)` `+3x^2 ` `+2x =0`

`x` (`x^(2)` `+3x+2) = 0`

`x(x+1)(x+2) =0`

`x=0 , ``x= -1 , x=-2`

rachellopez | Student, Grade 12 | (Level 1) Valedictorian

Posted on

To solve for the equation x^3+3x^2+2x=0 you have to factor. Start by factoring out the x that all the parts have in common.

x(x^2+3x+2)=0

Now you can easily factor the x^2+3x+2.

x(x+2)(x+1)=0

Now that you have factored as far as you can, you can set each factor equal to 0 and solve.

x=0              x+2=0           x+1=0

x=-2             x=-1

Your solutions are x=0, -2, and -1.