Solve for x: x^2 = 27
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We have to solve x^2 = 27 for x.
x^2 = 27
=> x^2 = 9*3
=> x^2 = 3^2 * 3
=> x = 3* sqrt 3 and - 3*sqrt 3
The required value is x = 3* sqrt 3 and x = -3*sqrt 3
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There are two answers…
x² = 27 27 can be expressed as a factor of perfect square 9 and 3
x² = 9*3 , by extracting the square root, we get both + and - solutions
Square root of 9 is +3 , square root of 3 is not perfect whole, so we can leave it as is
x = 3 ±√3
x = 3√3, -3√3
x = 5.196152423, -5.196152423.
We'll have to solve the quadratic equation:
x^2 = 27
We'll take square root both sides:
sqrt x^2 = sqrt 27
We'll write 27 = 3^3 = 3*3^2
|x| = 3sqrt3
The solutions of the equation are: {-3sqrt3 ; +3sqrt3}.
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