Solve for x : (x+1)^2 = 2x^2 - 5x + 11

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We have to solve (x+1)^2=2x^2-5x+11 for x.

(x+1)^2=2x^2-5x+11

open the brackets

=> x^2 + 2x + 1 = 2x^2 - 5x + 11

=> x^2 - 7x + 10 = 0

=> x^2 - 5x - 2x + 10 = 0

=> x(x - 5) - 2(x - 5) = 0

=> (x - 2)(x - 5) = 0

x - 2 = 0 => x = 2

and x - 5 = 0 => x = 5

The values of x are x = 5 and x = 2

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