We have to solve (x+1)^2=2x^2-5x+11 for x.
(x+1)^2=2x^2-5x+11
open the brackets
=> x^2 + 2x + 1 = 2x^2 - 5x + 11
=> x^2 - 7x + 10 = 0
=> x^2 - 5x - 2x + 10 = 0
=> x(x - 5) - 2(x - 5) =...
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We have to solve (x+1)^2=2x^2-5x+11 for x.
(x+1)^2=2x^2-5x+11
open the brackets
=> x^2 + 2x + 1 = 2x^2 - 5x + 11
=> x^2 - 7x + 10 = 0
=> x^2 - 5x - 2x + 10 = 0
=> x(x - 5) - 2(x - 5) = 0
=> (x - 2)(x - 5) = 0
x - 2 = 0 => x = 2
and x - 5 = 0 => x = 5
The values of x are x = 5 and x = 2