# Solve for x1/2 +7/10x =13/20

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We have to solve for x given the following equation: 1/2 +7/10x = 13/20.

1/2 + 7/10x = 13/20

multiply all terms with 20x

=> 1*20x/2 + 7*20x/10x = 13*20x/20

=> 10x + 7*2 = 13x

Subtract 10x from both the sides

=> 10x + 14 -10x = 13x - 10x

=> 13x - 10x = 14

=> 3x = 14

=> x = 14/3

**Therefore the required value of x is 14/3.**

1/2 +7/10x = 13/20 .To solve for x

Subtract 1/2 from both sides:

7/10x = 13/20-1/2 = 13/20 - 10/20 = (13-10)/10 = 3/20

7/10x = 3/20.

The denominators are 10x and 20. The LCM of the denominators are 20x. Therefore we multiply both sides by 20x

20x*7/10x = 20x*3/20

14 = 3x .

Divide both sides by 3:

14/3 = 3x/3.

14/3 = x.

Therefore x = 14/3 = 4 2/3.

We'll multiply by 20x the expression

20x/2 +7*20x/10x =13*20x/20

10x + 14 = 13x

We'll subtract 13x both sides:

10x - 13x + 14 = 13x - 13x

-3x + 14 = 0

We'll subtract 14 both sides:

-3x + 14 - 14 = -14

-3x = -14

We'll divide by -3:

x = -14/-3

**x = 4.(6)**

**The solution of the equation is admissible because it is different from 0.**