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tjbrewer eNotes educator| Certified Educator

`2^x-3=16`  we add 3 to each side and we get `2^x=19` We apply Logarithms to find the exponent and we get `log (2^x) = log 19` Applying the theorem `log_(a)x^p=p xx log_(a)x` we get `x log 2=log 19` This means `x=(log 19)/(log 2)` we put these into a calculator and we get `x~~14.111`

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