# Solve, write solution using set builders notation. show work -8 - 11 (3x + 7) < -40 x -9

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### 3 Answers

We have to solve for -8 - 11(3x + 7) < -40x -9

-8 - 11(3x + 7) < -40x -9

=> -8 - 33x - 77 < -40x - 9

=> 40x - 33x < 77 - 9 + 8

=> 7x < 76

=> x < 76/7

**The values of x are (76/7, -inf.)**

We are asked to solve the inequality -8-11(3x + 7) < -40x - 9

-8-11(3x + 7) <-40x -9

-8 -33x -77 < -40x - 9

-85 - 33x < -40x - 9

40x -33x - 85 < -40x + 40x -9

7x - 85 < - 9

7x - 85 + 85 < - 9 + 85

7x < 76

**x < 76/7**

**The answer is ( -infinity, 76/7)**

-8 - 11 ( 3x + 7 ) < -40x - 9

First distribute the -11

By distributing, you should get

**-8 - 33x -77 < -40x -9 **now combine the like terms ( - 8 with -77 )

By combining the like terms, you should get

**-85 - 33x < -40x - 9 **add -85 on both sides

By adding, you should get

**-33x < -40x + 76 **now add 40x on both sides

by adding, your should get

**7x < 76 **divide both sides by 7

By dividing, you should get

**x < 76/7 **

**your answer is (76/7, -inf.)**