`log20 = log(2*(10))`

I assume you are using the base 10 in your log.

According to logarithm laws, we know,

`log(ab) = loga + logb`

Therefore,

`log20 = log2+log10`

From table,

`log20 = 0.3010 + 1`

`log20 = 1.3010`

**The answer is 1.3010**

**Further Reading**