3x+ 2y = -6 ...........(1)
x + 3y = -2 ..............(2)
First we will solve algebraically.
Multiply (2) by -3 and add to (1).
==> 3x + 2y = -6
==> -3x -9y = 6
==> -7y = o ==> y= 0
==> 3x = -6 ==> x = -2
...
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3x+ 2y = -6 ...........(1)
x + 3y = -2 ..............(2)
First we will solve algebraically.
Multiply (2) by -3 and add to (1).
==> 3x + 2y = -6
==> -3x -9y = 6
==> -7y = o ==> y= 0
==> 3x = -6 ==> x = -2
Then, the solution is the point (-2,0)
Now we will verify by graphing both lines.
3x+2y = -6 ( black line)
x+ 3y = -2 (red line)
You can see that both lines intersects at the point (-2, 0) which is the solution of the system.