Solve this equation: log log x = 1 The answer is 10^10 but how is it solve?

Expert Answers

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log log x = 1

Let us assume that :

log x = y

Now substitute into the equation:

log (log x) = 1

==> log y = 1

Now we will rewrite:

==> y = 10^1 = 10

But we know that :

log x = y

==> log x = 10

==> x= 10^10

Approved by eNotes Editorial Team

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