x = 3y........(1)
3x + y = 10.........(2)
Using the substitution method, we will substitute x values from (1) in equation (2):
==> 3x + y = 10
==> 3(3y) + y = 10
==> 9x + y = 10
==> 10y = 10
==> y= 1
==> x= 3y...
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x = 3y........(1)
3x + y = 10.........(2)
Using the substitution method, we will substitute x values from (1) in equation (2):
==> 3x + y = 10
==> 3(3y) + y = 10
==> 9x + y = 10
==> 10y = 10
==> y= 1
==> x= 3y = 3*1 = 3
==> x= 3
2x + 7y = 1........(1)
2x - 2y = 9.........(2)
Using the elimination method, we will subtract (2) from (1):
==> 9y = -8
==> y= -8/9
Now to find x value , we will substitute with with either (1) or (2):
==> 2x - 2y = 9
==> 2x - 2(-8/9) = 9
==> 2x + 16/9 = 9
==> 2x = 9 - 16/9
==> 2x = 65/9
==> x= 65/18