# Solve the system using a matrix.x+3y=7=0 2x+y+4=0 3x+2y+11=0

giorgiana1976 | College Teacher | (Level 3) Valedictorian

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To solve the system, we'll have to re-write the equations:

x+ 3y +7 =0

We'll subtract 7 both sides:

x + 3y = -7 (1)

3x+2y +11=0

We'll subtract 11 both sides:

3x + 2y = -11 (2)

2x+y+4=0

We'll subtract 4 both sides:

2x + y = -4 (3)

We'll determine the matrix of the system. The determinant is formed from the coefficients of x and y.

1    3

A =  3    2

2    1

We'll take the first2 lines and columns of the matrix and we'll calculate the minor of the matrix A.

1    3

d =

3     2

d = 1*2 - 3*3 = 2 - 9 = -7

Now, we'll calculate the determinant that we'll tell us if the system has solution or not.

This determinant will be formed from the minor, the last row and the column of the terms from the right side of equal:

1    3    -7

C =  3     2   -11

2    1    -4

C = -2*4 - 7*3 - 3*2*11 + 2*2*7 + 11 + 3*3*4

C = - 8 - 21 - 66 + 28 + 11 + 36

C = 20  - 1 - 30

C = -11

Since C is not zero, the system has no solutions.

The system doesn't have solutions.