Solve the system of equations. 3x + 2y = 0 and 2x - y = 8

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The system of equations 3x + 2y = 0 and 2x - y = 8 has to be solved.

2x - y = 8

=> y = 2x - 8

substitute in 3x + 2y = 0

=> 3x + 2(2x - 8) = 0

=> 3x + 4x - 16 = 0

=> 7x = 16

=> x = 16/7

y = 32/7 - 8 = -24/7

The solution of the given system of linear equations is x = 16/7 and y = -24/7

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