# Solve the system of equations. 3x + 2y = 0 and 2x - y = 8

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### 2 Answers

The system of equations 3x + 2y = 0 and 2x - y = 8 has to be solved.

2x - y = 8

=> y = 2x - 8

substitute in 3x + 2y = 0

=> 3x + 2(2x - 8) = 0

=> 3x + 4x - 16 = 0

=> 7x = 16

=> x = 16/7

y = 32/7 - 8 = -24/7

**The solution of the given system of linear equations is x = 16/7 and y = -24/7**

3x + 2y =0 ......(i) 2x - y = 8.......(ii)

multiplying eq(ii) with 2 we get: 4x - 2y = 16........(iii)

adding eq(i) and (iii) we get : 7x =16

Thus, x = 16/7.

Now, substituing value of x in eq(i) we get:(3*16/7)+2y = 0

=> 48/7+2y = 0

=> y = -48/14

=> y = -24/7.

Thus x = 16/7 , y = -24/7