Solve the system of equations `a+2b=3` `a^2+b^2=26`

Expert Answers
lemjay eNotes educator| Certified Educator



To solve, apply substitution method. To do so, solve for a in the first equation.




Then, plug-in this to the second equation.





Set one side equal to zero.



Then, factor.


Set each factor equal to zero and solve for b.

`5b-17=0`       and      ` b+1=0`

          `b=17/5`                     `b=-1`

Next, solve for a. To do so, plug-in the values of b to a=3-2b.

`b=-1, a=3-2(-1)=3+2=5`

`b=17/5, a=3-2(17/5)=3-34/5=15/5-34/5=-19/5`

Hence, the solutions to the system of equations are:

> `a=5` , `b=-1`

> `a=-19/5` 5,  `b =17/5`

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