Solve the system 2x-4y = 5 x+3y = 7
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We have the two equations 2x-4y = 5 and x+3y = 7 to solve for x.
x+3y = 7 can be rewritten in terms of x as x = 7 - 3y.
Now substitute x = 7 - 3y in 2x-4y = 5
=> 2( 7 - 3y) - 4y = 5
=> 14 - 6y - 4y = 5
=> -10y = 5 - 14
=> -10 y = -9
=> y = 9/10
As x = 7 - 3y
=> x = 7 - 27/10
=> x = (70 - 27)/10
=> x = 43/ 10
Therefore x= 43/10 and y = 9/10
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calendarEducator since 2008
write3,662 answers
starTop subjects are Math, Science, and Social Sciences
2x - 4y = 5 ............(1)
x + 3y = 7 .............(2)
We will use the elimination method to solve for x and y.
We will multiply (2) by -2 and add to (1).
==> 2x -4y = 5 ..............(1)
==> -2x - 6y = -14 ............2*(2)
==> -10y = -9
==> y = 9/10 = 0.9
Now to find x we will substitute into (2).
==> x = 7 - 3y = 7- 3(0.9) = 7- 2.7 = 4.3
==> x = 4.3
Then, the solution to the system is the pair ( 4.3 , 0.9)
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