Question

solve the system
2x + 3y = 8
x + 8y = 17

Accepted Answer

2x + 3y = 8........(1)
x+ 8y = 17.........(2)
using the elimination method, we will multiply (2) by -2 and then add to (1):
==> 2x + 3y = 8
==> -2x - 16y = -34
Now add both equations:
==> -13y = - 26
Now divide by -13
==> y= 2
Now to find x, we will substitute in (1):
2x+ 3y = 8
2x + 3*2 = 8
==> 2x = 2
==> x= 1

Answer

2x+3y = 8.....(1)
x+8y = 17.......(2)
To solve the equation we  eliminate x :
Eq(1) -2*eq(2) gives:
(2x+3y)-2(x+8y) = 8-2*17
3y-16y = 8-34
-13y = -26.
y = -26/-13 = 2.
Now put y = 2 in eq (2):
x+8*2 = 17
x = 17-8*2 = 17-16 = 1.
Therefore x = 1 and y = 2.

Answer

We'll solve the system of equations using the elimination method, also:
2x+3y= 8 (1)
x+8y= 17 (2)
We'll multiply (2) by -2:
-2x - 16y = -34 (3)
We'll add (3) to (1):
2x + 3y - 2x - 16y = 8 - 34
We'll combine like terms:
-13y = -26
We'll divide by -13 both sides:
y = 2
We'll substitute y = 2 in (2):
x+8y= 17
x + 16 = 17
We'll subtract 16 both sides:
x = 17 - 16
x = 1
The solution of the given system is {(1 , 2)}.
We could also use the substitution method. We'll write x with respect to y, from the equation (2).
x+8y= 17
x = 17 - 8y (3)
We'll substitute x in (1):
2(17 - 8y)+3y= 8
We'll remove the brackets:
34 - 16y + 3y = 8
We'll combine like terms:
-13y = 8 - 34
-13y = -26
We'll divide by -13:
y = 2
We'll substitute y in (3):
x = 17 - 16
x = 1

Math

solve the system 2x + 3y = 8 x + 8y = 17

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