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Solve The Negaive Definite Integral. Solve This When a=3, b=1 and f(x)=(x^2+x)

Expert Answers

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To find the value of the integral of f(x)=(x^2+x), between the limits 1 and 3, we find the integral

Int[ f(x) dx ], x = 1 to x = 3

=> (x^3/3 + x^2/2), x = 1 to x = 3

=> 3^3/3 + 3^2/2 - 1^3/3 - 1^2/2

=> 9 + 9/2 - 1/3 - 1/2

=> 38/3

The required value if the definite integral is 38/3

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