Solve for n `3^(n-2) = 27`
It can be written as:
Comparing the left hand side and the right hand side we get,
which means n=5
27 on the right hand side can be written as 3^3 thereby allowing the same base (3) to be present on both sides. Therefore, the bases can be ignored and the resulting equation becomes:
you can add two to both sides and the answer becomes:
First, let x = n-2. With substitution, we now have 3^x = 27.
We know that x must equal 3, whether that's because the fact is memorized or because 27 divided by 3 produces 1 after dividing three times.
Therefore, x = 3 = n-2.
3 = n-2 (add 2 to both sides)
5 = n
At first we know that.........
3^3= 27 So therefore we can write....
3^n-2 = 3^3 next
n-2 = 3. After that, you would add 2 on either side to get n = 5.
Soo we get n=5!!
Since 3^3=27, you can replace the 27 in the equation with 3^3:
Now you can cancel out the bases since they are the same number. You are left with:
n=5. This is the answer.
When we solve for exponents it is easier if the bases are the same:
We know that 27 can be simplified as `3^3 ` because `3 x 3 x 3 = 27`
set the exponents equal to each other:
`3^(n-2) = 3^3`
`n - 2 = 3`
get n alone by adding 2 to both sides:
`n = 5`
To solve this question, you would have to make sure that the numbers on either side of the equal sign have the same base. 27 also equals 3^3, so therefore you can write 3^n-2 = 3^3. Then, taking out the bases (since they are the same), you would be left with n-2 = 3. After that, you would add 2 on either side to get n = 5.
We know that 3^3=27, so set the equation up to be n-2=3. To solve this equation, add two to both sides and you get n=5.