solve log5(x-4)=log7x for x

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hala718 | High School Teacher | (Level 1) Educator Emeritus

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log 5(x-4) = log 7x

Since we have logarithm with the same bases, then the expression inside the lofarithms are equal.

==> 5(x-4)= 7x

Now we will solve for x.

==> 5x - 20 = 7x

==> -2x = 20

==> x = -10

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